_{em}for the Sun.

- Recall, that the electric Planck constant h
_{em}for the pair determined by a relatively small charge Z and the charged system with large charge Q, is as a generalization of the gravitational Planck constant determined by the formula h_{em}= Qe^{2}/β_{0}, where β_{0}=v_{0}/c <1 is a velocity parameter.For the Earth, there are reasons to believe that β

_{0}≈ 1 holds true in the gravitational case. This implies that h_{em}has minimal value. For the inner planets of the Sun, Mercury, Venus, and Earth, one has in a good approximation β_{0,S}= 2^{-11}as was deduced by Nottale. For the outer planets, one would have β_{0}=2^{-11}/5. - The charge is identified as the electric flux over a surface containing the charge. In the case of a spherically symmetric charge density within a sphere of radius R one has
Q = ε

_{0}ES= ε_{0}× E(R)× 4π R^{2},where ε

_{0}= 8.85× 10^{-12}C/Vm is the dielectric constant of vacuum. Note that one has E(R) ∝ 1/R^{2}. One can restrict the consideration to the surface of the system so that E(R) is the electric field at the surface, S is the surface area of the sphere, and R is the radius of the sphere. - One can use the scaling law
Q
_{S}/Q_{E}= (E_{S}/E_{E})× (R_{S}/R_{E})^{2}.to deduce Q

_{S}for the Sun from Q_{E}. From the values R_{S}≈ 6.9 × 10^{8}m and R_{E}≈ 6.3× 10^{6}m, one has R_{S}/R_{E}≈ 101.For the Earth one has E

_{E}=.1-.3 keV/m. For the charge of Earth one obtains the estimate Q≈ 4.4x× 10^{6}C =27.5× 10^{24}e. To get some perspective, note that aluminium capacitors can have a maximum charge of about 10^{3}C whereas the maximal charge of a van de Graaff generator is about .14 C. From C= 6.24 × 10^{18}e one obtains ℏ_{em,E}≈ 2.75x × 10^{25}/β_{0,E}, x in the range [1,3].The value of the electric field at the surface of the Sun is E

_{S}= 1.5 V/m: this gives E_{S}/E_{E}= x× 10^{-2}, x in the range [1,3] andQ

_{S}/Q_{E}≈eq x× 100, x in the range [1.3,.43] . - Using these data, one can estimate the ratio h
_{eff,S}/h_{eff,E}. For the inner planets (Mercury, Venus, Earth), in the case of gravity, β_{0,E}=1 and β_{0,S}= 2^{-11}. If one assumes the same values in the electric case, one obtains the estimateh

_{eff,S}>/h_{eff,E}= (Q_{S}/Q_{E}) × (β_{0,E}/β_{0,S}) .h

_{eff,E}= E_{E}4π R^{2}/β_{0,E}has been already estimated and is much larger than the gravitational Planck constant.

- In the case of the Earth, the electric Compton wavelength Λ
_{em}= h_{em}/m for proton is Λ_{em,p}≈ x× 650 km, x in the range [.33.,1] for a proton (m=m_{p}). There are numerical factors of order 1 involved. The radius of the thermosphere is about 340-350 km, one half of the upper bound. This puts bells ringing since the thermosphere is the area where the terrestrial plasmoids live!The gravitational Compton length of the Earth is same for all particles and given by Λ

_{gr}=.5 cm. One hasΛ

_{em,p}/Λ_{gr}≈ 1.3x × 10^{8}.In the number theoretic sense, the electric body would be considerably smarter than the gravitational body.

For a capacitor with capacitance of 1 μF and at voltage 1 V, the charge would be 1 μ C. For β

_{0}=1 would have Λ_{em,p}/Λ_{gr}≈ 2.9× 10^{-3}so that one would have Λ_{em,p}≈ 1.5 × 10^{-5}m. Could electronic systems be intelligent and conscious at least on this scale? - The electric Compton wavelength of the proton for the Sun would be obtained from the scaling law
Λ

_{em,S}/Λ_{em,E}= h_{em,S}/h_{em,E}= (Q_{S}/Q_{E}) (β_{0,E}/β_{0,S})from that for the Earth. This gives

Λ

_{em,S}/Λ_{em,E}≈ 2× 10^{5}/x, x in the range [.33,1].For the proton this would give Λ

_{em,S}≈ 1.3x× 10^{8}km for β_{0,S}=2^{-11}. The astronomical unit AU, that is the distance of the Earth from the Sun is AU= 1.5 × 10^{8}km! The Earth would live on the outskirts of the thermosphere, assignable to the inner planets of the Sun? Could this be a mere coincidence?The interpretation would be in terms of a hierarchy of electric and magnetic bodies and the electric body for the Sun + inner planets would be near the top of the hierarchy.

- What about the outer planets? Nottale noticed that for the outer planets β
_{0}scales by a factor of 1/5 to β_{0}= 2^{-11}/5 so that the electric Compton wavelength at the level of the entire planetary system would be about 5AU. The corresponding thermosphere can accommodate Mars, whose radius is roughly 4 times the radius of Earth, but no other outer planets. Mars and Sun living at the outer boundaries of two thermospheres of Sun would be very special in that the thermal gradients of plasma would be very strong: this is the prerequisite for self-organization as development of complexity. Mars and Sun would have a very special position in the planetary system.

For a summary of earlier postings see Latest progress in TGD.

For the lists of articles (most of them published in journals founded by Huping Hu) and books about TGD see this.

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